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(P)=-6P^2+60P-126
We move all terms to the left:
(P)-(-6P^2+60P-126)=0
We get rid of parentheses
6P^2-60P+P+126=0
We add all the numbers together, and all the variables
6P^2-59P+126=0
a = 6; b = -59; c = +126;
Δ = b2-4ac
Δ = -592-4·6·126
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-\sqrt{457}}{2*6}=\frac{59-\sqrt{457}}{12} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+\sqrt{457}}{2*6}=\frac{59+\sqrt{457}}{12} $
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